Chapter 7 Notes, Precalculus 3e Stitz/Zeager

Author

Chalmeta

7 Conic Sections

7.2 Circles

A circle with center \((h, k)\) and radius \(r>0\) is the set of all points \((x,y)\) in the plane whose distance to \((h,k)\) is \(r\).

Standard Equation of a Circle: The standard equation of a circle with center \((h, k)\) and radius \(r>0\) is \[(x-h)^2 + (y-k)^2=r^2\]

Diagram of generic circle with center point labeled (h,k) and radius r marked from center to a point on the circle, illustrating the standard equation of a circle in coordinate plane

TipExample 1

Write the equation of the circle centered at \((6,9)\) with radius 20.

TipExample 2

Find the standard form for the equation of a circle \[(x-h)^2 + (y-k)^2=r^2\] with a diameter that has endpoints \((5,-2)\) and \((3,9)\)

TipExample 3

Write the equation of the circle centered at \((4,6)\) that passes through \((8,13)\).

TipExample 4

Complete the square to convert to the standard form of a circle and find the center and radius for \[x^2 +y^2 -5x+4y-5=0\]

7.3 Parabolas

The Parabola

A parabola is the set of all points in a plane equidistant from a fixed point \(F\) (the focus) and a fixed line \(L\) (the directrix) in the plane.

Diagram of parabola showing the focus point F, directrix line, vertex V halfway between focus and directrix, and demonstrating that any point P on the parabola has equal distances d1 and d2 to the focus and directrix respectively

\(d_1=d_2\).

The vertex \(v\) is halfway between the focus and the directrix.

Standard Equations for Parabolas

\((y-k)^2 = 4p(x-h)\) Horizontal axis.

If \(p > 0\) it opens right

If \(p < 0\) it opens left

\((x-h)^2 = 4p(y-k)\) Vertical axis.

If \(p > 0\) it opens up

If \(p < 0\) it opens down

Vertex always located at \((h, k)\).

Focus: \(p\) units from the vertex.

Directrix: \(p\) units from the vertex.

TipExample 5

Find the vertex, focus and directrix for the parabola and sketch the graph. \[y^2+6y +8x + 25 = 0\]

We want the equation to be in form \((y-k)^2 = 4p(x-h)\) so we need to complete the square.

Coordinate grid paper for graphing parabola with vertex, focus, and directrix after completing the square

TipExample 6

Find the standard form of the equation of the parabola with its vertex at the origin and directrix \(y = -3\)

Step 1: Graph the parabola so that we know what it looks like.

Coordinate grid showing parabola with vertex at origin and directrix line at y equals negative 3, demonstrating parabola opening upward

TipExample 7

Find the standard form of the parabola with vertex (-1, 2) and focus (-1, 0). Sketch the parabola.

Coordinate grid for graphing parabola with vertex at negative 1 comma 2 and focus at negative 1 comma 0, indicating downward opening parabola with vertical axis of symmetry

TipExample 8

Find the vertex, focus and directrix for the parabola and sketch the graph. \[y=\frac{1}{4}(x^2 - 2x +5)\]

Step 1: Clear the denominator.

Coordinate grid paper for graphing parabola after clearing denominator and completing the square to find vertex, focus, and directrix

7.4 Ellipse

An ellipse is the set of all points \(P\) in a plane such that the sum of the distances of \(P\) from two fixed points (\(F\) and \(F'\)) in the plane is constant. \(F\) and \(F'\) are called the foci (plural of focus).

Diagram of ellipse showing center (h,k), two foci F and F prime, vertices v and v prime on major axis, minor axis vertices, illustrating that sum of distances d1 plus d2 from any point to both foci is constant

\(d_1 + d_2 =\) constant.

\(F\) and \(F'\) are the foci.

\(v\) and \(v'\) are vertices.

\((h, k)\) is the center.

Label the diagram above with the following:

  1. major axis
  2. minor axis
  3. minor axis vertices: \(B\) and \(B'\)
  4. distance from foci to center: \(c\)
  5. distance from vertices to center: \(a\) (major axis) and \(b\) (minor axis)

By using the distance formula we can derive a generic equation for an ellipse.

Standard Equations for Ellipse

Center always located at \((h, k)\).

Major axis length: \(2a\)
Minor axis length: \(2b\)

where \(0 < b < a\)

Horizontal major axis Vertical major axis
\(\displaystyle \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\) \(\displaystyle \frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1\)

The foci lie on the major axis \(c\) units from the center with \[c^2 = a^2 - b^2\]

TipExample 9

Sketch the graph, find the foci, and the lengths of the major and minor axes for \[\frac{x^2}{4} + \frac{y^2}{9} = 1\]

Coordinate grid paper for graphing ellipse with vertical major axis, center at origin, for determining foci and axis lengths

TipExample 10

Sketch the graph, find the foci, and the lengths of the major and minor axes for \[x^2 + 9y^2 = 9\]

Coordinate grid paper for graphing ellipse with horizontal major axis after converting equation to standard form

TipExample 11

Sketch the graph, find the foci, and the lengths of the major and minor axes for \[9x^2 + 4y^2 - 54x + 40y +37 = 0\]

Need: \(\displaystyle \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\) so we complete the square, twice. Once for the \(x\)’s and once for the \(y\)’s.

Coordinate grid paper for graphing ellipse after completing the square for both x and y terms to convert to standard form

TipExample 12

Find the standard form of the equation of the ellipse with:

Center (3, 2),

Foci: (1, 2) and (5, 2) and

\(a = 3c\).

Coordinate grid paper for constructing ellipse equation given center and foci locations on horizontal major axis

7.5 Hyperbola

A hyperbola is the set of all points \(P\) in a plane such that the absolute value of the differences of the distances of \(P\) to two fixed points (\(F\) and \(F'\)) in the plane is positive constant. \(F\) and \(F'\) are called the foci (plural of focus).

Diagram of hyperbola with horizontal transverse axis centered at origin, showing two branches opening left and right, foci F and F prime on x-axis, vertices, and asymptotes, with equation x squared over a squared minus y squared over b squared equals 1

\(\displaystyle \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\)

Center (0, 0)

\(x\)-int: (-\(a\), 0) and (\(a\), 0)

\(y\)-int: NONE

Foci: \(F\) (-\(c\), 0) and \(F'\) (\(c\), 0). \[c^2 = a^2+b^2\]

Transverse axis length = 2\(a\)

Conjugate axis length = 2\(b\)

Diagram of hyperbola with vertical transverse axis centered at origin, showing two branches opening up and down, foci F and F prime on y-axis, vertices, and asymptotes, with equation y squared over a squared minus x squared over b squared equals 1

\(\displaystyle \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\)

Center (0, 0)

\(x\)-int: NONE

\(y\)-int: (0,-\(a\)) and (0,\(a\))

Foci: \(F\) (0,-\(c\)) and \(F'\) (0,\(c\)). \[c^2 = a^2+b^2\]

Transverse axis length = 2\(a\)

Conjugate axis length = 2\(b\)

TipExample 13

Sketch, find foci and axis lengths for \[\frac{y^2}{4} - \frac{x^2}{9} = 1\]

Coordinate grid paper for graphing hyperbola with vertical transverse axis centered at origin

TipExample 14

Sketch, find foci and axis lengths for \[9y^2-16x^2=144\]

Coordinate grid paper for graphing hyperbola after converting to standard form

Standard Equations for Hyperbola

Center always located at \((h, k)\).

Transverse axis length: \(2a\)
Conjugate axis length: \(2b\)

where \(a > 0\) and \(b > 0\)

Horizontal transverse axis (\(x\)-intercepts) Vertical transverse axis (\(y\)-intercepts)
\(\displaystyle \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\) \(\displaystyle \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1\)

Diagram of hyperbola with horizontal transverse axis centered at (h,k), showing two branches, foci, vertices, center point, asymptote box, and asymptote lines for constructing the graph

Diagram of hyperbola with vertical transverse axis centered at (h,k), showing two branches, foci, vertices, center point, asymptote box, and asymptote lines for constructing the graph

The foci lie on the transverse axis \(c\) units from the center with \[c^2 = a^2 + b^2\]

The asymptote “box” for drawing is determined by:

\(\pm a\) along the transverse axis from the center
\(\pm b\) along the conjugate axis from the center

TipExample 15

Convert to a standard equation and graph the following: \[-9x^2 + 16y^2 -72x - 96y - 144 = 0\]

Coordinate grid paper for graphing hyperbola after completing the square and converting to standard form with vertical transverse axis

TipExample 16

Convert to a standard equation and graph the following: \[x^2 - 9y^2 + 36y - 72 = 0\]

Coordinate grid paper for graphing hyperbola after completing the square and converting to standard form with horizontal transverse axis